JEE Advanced 2009Paper 2
- Exam
- JEE Advanced
- Year
- 2009
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Advanced 2009 · Paper 2 · Mathematics · Definite Integration
Let f: R arrow R be a continuous function, which satisfies...
Let be a continuous function, which satisfies . Then, the value of is
Correct answer
0
Step-by-step solution
From given integral equation, . Also, differentiating the given integral equation w.r.t. , we get
\begin{gathered} f^{\prime}(x)=f(x) \\
\text{ If } \quad f(x) ≠ 0 \Rightarrow \frac{f^{\prime}(x)}{f(x)}=1 \\
\Rightarrow \quad \log f(x)=x+C \Rightarrow f(x)=e^C e^x \\
\because f(0)=0 \Rightarrow e^C=0, \text{ a contradiction }\\
\therefore f(x)=0, \forall x \in R \Rightarrow f(\ln 5)=0
\end{gathered}