JEE Advanced2006MathematicsDefinite IntegrationActual
Match the following.
Options
- A(i) (a), (ii) (b), (iii) (d), (iv) (c)
- B(i) (c), (ii) (a), (iii) (b), (iv) (d)
- C(i) (a), (ii) (d), (iii) (b), (iv) (c)
- D(i) (b), (ii) (a), (iii) (c), (iv) (d)
Correct answer
C. (i) (a), (ii) (d), (iii) (b), (iv) (c)
Step-by-step solution
(i) I= ₀^ / 2 ( x)^ x ( x x- ( x)^ x ) d x= ₀^ / 2 d d x ( x)^ x d x=1 (ii) The point of intersection of -4 y^2=x and x-1=-5 y^2 is (-4,-1) and (-4,1) . Hence, required area =2 ₀^1 (1-5 y^2 ) d y- ₀^1-4 y^2 d y = 4 3 . (iii) The point intersection of y=3^ x-1 x and y=x^x-1 is (1,0) . Hence, d y d x = 3^ x-1 x +3^ x-1 3 x ( d y d x )_ (1,0) =1 For ( d y d x )_ (1,0) =1 If is angle between the curves, then =0 . =0^ (iv) aligned & d y d x = 2 x+y d x d y - x 2 = y 2 & x e^ -y / 2 = 1 2 y e^ -y / 2 d y & x+y+2=k e^ y /