Let S=\ A=( array lll 0 & 1 & c 1 & a & d 1 & b & e array ): a, b,...

(|A|=-(e-d)+c(b-a)= $\pm$1) Case (i) : (c=0 \Rightarrow(e, d)=(1,0),(0,1) → 2) ways b$and$a can be each 2 ways (\Rightarrow) Total $=8$ ways Case (ii) : (c ≠ 0 \Rightarrow c=1) (\Rightarrow d-e+b-a=$\pm$1) ($$\begin{array}{llll}1 & 1 & 1 & 0 \\ 1 & 1 & 0 & 1 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1\end{array}$$\right\} → 4\times$2=8) ways Total$=16$ways$