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JEE Advanced 2026Paper 1
Exam
JEE Advanced
Year
2026
Paper
Paper 1
Subject
Mathematics
Chapter
Matrices

JEE Advanced 2026 · Paper 1 · Mathematics · Matrices

Which one of the following matrices can be obtained by performing...

Which one of the following matrices can be obtained by performing elementary row transformations on the 3×33 \times 3 identity matrix?

Options

  1. A[111111111]\begin{bmatrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 1 \end{bmatrix}
  2. B[111234121]\begin{bmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 1 & 2 & 1 \end{bmatrix}
  3. C[111234258]\begin{bmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 2 & 5 & 8 \end{bmatrix}
  4. D[111−112023]\begin{bmatrix} 1 & 1 & 1 \\ -1 & 1 & 2 \\ 0 & 2 & 3 \end{bmatrix}

Correct answer

B. [111234121]\begin{bmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 1 & 2 & 1 \end{bmatrix}

Step-by-step solution

Any matrix obtained by performing elementary row transformations on the identity matrix is equivalent to the identity matrix, which means it must be non-singular (invertible). Therefore, its determinant must be non-zero.

Evaluating the determinant of the matrix in option (A):
∣111111111∣=0\begin{vmatrix} 1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 1 \end{vmatrix} = 0

Evaluating the determinant of the matrix in option (B):
∣111234121∣=1(3−8)−1(2−4)+1(4−3)=−5+2+1=−2≠0\begin{vmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 1 & 2 & 1 \end{vmatrix} = 1(3 - 8) - 1(2 - 4) + 1(4 - 3) = -5 + 2 + 1 = -2 \neq 0

Evaluating the determinant of the matrix in option (C):
∣111234258∣=1(24−20)−1(16−8)+1(10−6)=4−8+4=0\begin{vmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 2 & 5 & 8 \end{vmatrix} = 1(24 - 20) - 1(16 - 8) + 1(10 - 6) = 4 - 8 + 4 = 0

Evaluating the determinant of the matrix in option (D):
∣111−112023∣=1(3−4)−1(−3−0)+1(−2−0)=−1+3−2=0\begin{vmatrix} 1 & 1 & 1 \\ -1 & 1 & 2 \\ 0 & 2 & 3 \end{vmatrix} = 1(3 - 4) - 1(-3 - 0) + 1(-2 - 0) = -1 + 3 - 2 = 0

Since only the matrix in option (B) has a non-zero determinant, it is the only one that can be obtained from the identity matrix by elementary row transformations.

Answer: [111234121]\begin{bmatrix} 1 & 1 & 1 \\ 2 & 3 & 4 \\ 1 & 2 & 1 \end{bmatrix}
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