JEE Main202624 January 2026Evening ShiftMathematicsMatricesActual
Let f(x)= 7 x¹⁰+9 x⁸ (1+x²+2 x⁹ )² d x, x>0, _ x 0 f(x)=0 and f(1)= 1 4 . If A = [ array ccc 0 & 0 & 1 1 4 & f^ (1) & 1 ² & 4 & 1 array ] and B = adj ( adj A ) be such that | B |=81 , then ² is equal to
Options
- A2
- B1
- C3
- D4
Correct answer
D. 4
Step-by-step solution
Divide numerator and denominator by x¹⁸ , let t = x⁻⁹ + x⁻⁷ + 2 , then dt = -(9x⁻¹⁰+7x⁻⁸)dx . f(x) = 1 t + C = x^9 1+x^2+2x^9 + C . _ x 0 f(x) = 0 C = 0 . f(1) = 1 4 (verified). f'(x) = 9x^8(1+x^2+2x^9) - x^9(2x+18x^8) (1+x^2+2x^9)^2 . f'(1) = 36-20 16 = 1 . |A| = vmatrix 0 & 0 & 1 1/4 & 1 & 1 ^2 & 4 & 1 vmatrix = 1 - ^2 . |B| = | adj ( adj A)| = |A|^ (3-1)^2 = (1- ^2)^4 = 81 = 3^4 . |1- ^2| = 3 ^2 = 4 .