JEE Advanced2016MathematicsMatricesActual
Let P = 3 - 1 - 2 2 0 α 3 - 5 0 , where α ∈ R , Suppose Q = q i j is a matrix such that P Q = k I , where k ∈ R , k ≠ 0 and I is the identity matrix of order 3. If q 23 = - k 8 and det ⁡ Q = k 2 2 then
Options
- Aα = 0 , k = 8
- B4 α - k + 8 = 0
- Cdet P a d j Q = 2 9
- Ddet Q (a d j P) = 2 13
Correct answer
B. 4 α - k + 8 = 0
Step-by-step solution
P Q = k I P Q = k 3      ( as order is 3 ) ⇒ P = 2 k   ≠ 0     ⇒     P is an invertible matrix ∵ P Q = k I ∴ Q = k P - 1   I = K 1 P adj P ∴ Q = a d j . P 2 ∵ q 23 =   - k 8 ( ∴ cofactor P 32 = - 3 α + 4 ) ⇒ 12 α + 16 = K & adjP 2 = P 32 2 T - q 23 ∴ undefined ...... (i) Also P = 2 k ⇒ k = 10 + 6 α ......(ii) Solving these two ⇒ 12 α + 16 = 10 + 6 α ⇒ α =