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JEE Advanced 2009Paper 2
Exam
JEE Advanced
Year
2009
Paper
Paper 2
Subject
Mathematics
Chapter
Parabola

JEE Advanced 2009 · Paper 2 · Mathematics · Parabola

The tangent P T and the normal P N to the parabola y^2=4 a x at a...

The tangent PTP T and the normal PNP N to the parabola y2=4axy^2=4 a x at a point PP onThe tangent P T and the normal P N to the parabola y^2=4 a x at a point P on

Options

  1. Avertex is (2a3,0)\left(\frac{2 a}{3}, 0\right) it meet its axis at points TT and NN,
  2. Bdirectrix is x=0x=0 respectively. The locus of the centroid of △PTN\triangle P T N is a parabola whose
  3. Clatusrectum is 2a3\frac{2 a}{3}
  4. Dfocus is (a,0)(a, 0)

Correct answer

A. vertex is (2a3,0)\left(\frac{2 a}{3}, 0\right) it meet its axis at points TT and NN,

Step-by-step solution

Equation of tangent and normal at point P(at2,2at)P\left(a t^2, 2 a t\right) is ty=x=at2t y=x=a t^2 and y=−tx+2at+at2y=-t x+2 a t+a t^2 Let centroid of △PTN\triangle P T N is R(h,k)R(h, k). ∴h=at2+(−at2)+2a+at23\therefore \quad h=\frac{a t^2+\left(-a t^2\right)+2 a+a t^2}{3} and k=2at3k=\frac{2 a t}{3} The tangent P T and the normal P N to the parabola y^2=4 a x at a point P on
\begin{array}{rlrl} & \Rightarrow & 3 h & =2 a+a \cdot\left(\frac{3 k}{2 a}\right)^2 \\ \Rightarrow & & 3 h & =2 a+\frac{9 k^2}{4 a} \\ \Rightarrow & 9 k^2 & =4 a(3 h-2 a) \end{array} ∴\therefore Locus of centroid is y2=4a3(x−2a3)y^2=\frac{4 a}{3}\left(x-\frac{2 a}{3}\right) ∴Vertex⁡(2a3,0)\therefore \operatorname{Vertex}\left(\frac{2 a}{3}, 0\right); directrix x−2a3=−a3⇒x=a3x-\frac{2 a}{3}=-\frac{a}{3} \Rightarrow x=\frac{a}{3} Latusrectum =4a3=\frac{4 a}{3} ∴\therefore Focus \left(\frac{a}{3}+\frac{2 a}{3}, 0\right)i.e.i.e.(a, 0)
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