JEE Advanced2010MathematicsThree Dimensional GeometryActual
If the distance of the point P(1,-2,1) from the plane x+2 y-2 z= , where >0 , is 5 , then the foot of the perpendicular from P to the plane is
Options
- A( 8 3 , 4 3 ,- 7 3 )
- B( 4 3 ,- 4 3 , 1 3 )
- C( 1 3 , 2 3 , 10 3 )
- D( 2 3 ,- 1 3 , 5 2 )
Correct answer
A. ( 8 3 , 4 3 ,- 7 3 )
Step-by-step solution
Distance of point P from plane =5 gathered = | 1-4-2- 3 | =10 gathered Foot of perpendicular aligned x-1 1 & = y+2 2 = z-1 -2 = 5 3 x & = 8 3 , y= 4 3 , z=- 7 3 aligned Thus, the foot of the perpendicular is A ( 8 3 , 4 3 ,- 7 3 )