JEE Main20264 April 2026Morning ShiftMathematicsThree Dimensional GeometryActual
The square of the distance of the point (-2, -8, 6) from the line x-1 1 = y-1 2 = z -1 along the line x+5 1 = y+5 -1 = z 2 is equal to:
Options
- A3
- B6
- C8
- D12
Correct answer
B. 6
Step-by-step solution
Let the given point be P(-2, -8, 6) . The distance is measured along the line x+5 1 = y+5 -1 = z 2 , which has direction ratios (1, -1, 2) . The equation of the line passing through P and parallel to this line is: x+2 1 = y+8 -1 = z-6 2 = Any point on this line can be written as Q( - 2, - - 8, 2 + 6) . Since Q lies on the line x-1 1 = y-1 2 = z -1 , we substitute the coordinates of Q into its equation: - 2 - 1 1 = - - 8 - 1 2 = 2 + 6 -1 - 3 1 = - - 9 2 = 2 + 6 -1 Taking the first two parts: 2( - 3) = - - 9 2 - 6 =