In the following circuit C _ 1 = 12μ F, C _ 2 = C _ 3 = 4μ F and C...

In the following circuit ${C}_{1} = 12\mu F, {C}_{2} = {C}_{3} = 4\mu F$ and ${C}_{4} = {C}_{5} = 2\mu F$ . The charge stored in ${C}_{3}$ is $\mu C .$

In the following circuit C _ 1 = 12μ F, C _ 2 = C _ 3 = 4μ F and C _ 4 = C _ 5 = 2μ F . The charge stored in C _ 3 is μ

Correct answer

Step-by-step solution

From circuit given,
Capacitors ${C}_{2}, {C}_{3}, {C}_{4}$ and ${C}_{5}$ are in parallel connection with constant potential difference as $2V$ .
Now, charge stored in ${C}_{3}$ is ${Q}_{3} = 2 \times 4\mu C$ $= 8\mu C$ .

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