In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C. The switch S₁ is pressed first to fully charge the capacitor C₁ and the released. The switch S₂ is then pressed to charge the capacitor C₂. After some time, S₂ is released and then is S₃ pressed. After some time,

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In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C. The switch S₁ is pressed first to fully charge the capacitor C₁ and the released. The switch S₂ is then pressed to charge the capacitor C₂. After some time, S₂ is released and then is S₃ pressed. After some time,
In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C . The switch S 1 is

Quantrex Academy · Accepted Answer

Correct answer: B. the charge on the upper plate of C 1 is CV 0 .

When S 1 is closed, charge on C _ 1 = 2 V _ 0 C After S 2 is closed, half of the change will move to C 2 ∴ charge on C _ 1 = (1)/(2) 2 V _ 0 C when S 2 is closed, charge on C _ 2 = V _ 0 C but with reversed polarity, ∴ Charge on upper plate = - V _ 0 C

In the circuit shown in the figure, there are two parallel plate...

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