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JEE Advanced 2016Paper 2
Exam
JEE Advanced
Year
2016
Paper
Paper 2
Subject
Physics
Chapter
Current Electricity

JEE Advanced 2016 · Paper 2 · Physics · Current Electricity

Consider two identical galvanometers and two identical resistors...

Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the galvanometers Rc<R2,{R}_{c} < \dfrac{R}{2}, which of the following statement(s) about any one of the galvanometers
is(are) true ?Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of theConsider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of theConsider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of theConsider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the

Options

  1. AThe maximum voltage range is obtained when all the components are connected in series
  2. BThe maximum voltage range is obtained when the two resistors and one galvanometer are connected in series, and the second galvanometer is connected in parallel to the first galvanometer
  3. CThe maximum current range is obtained when all the components are connected in parallel
  4. DThe maximum current range is obtained when the two galvanometers are connected in series and the combination is connected in parallel with both the resistors.

Correct answer

B. The maximum voltage range is obtained when the two resistors and one galvanometer are connected in series, and the second galvanometer is connected in parallel to the first galvanometer

Step-by-step solution

Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the
i=E2R+2RcVg1=iRc=ERc2(R+Rc)=ERc2R+2Rci = \dfrac{E}{2R + 2{R}_{c}} {V}_{{g}_{1}} = i{R}_{c} = \dfrac{E{R}_{c}}{2\left(R + {R}_{c}\right)} = \dfrac{E{R}_{c}}{2R + 2{R}_{c}}
Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the
i2=E2R+Rc2Vg2=i22×Rc{i}_{2} = \dfrac{E}{2R + \dfrac{{R}_{c}}{2}} {V}_{{g}_{2}} = \dfrac{{i}_{2}}{2} \times {R}_{c}
=12(E2R+Rc2)×Rc= \dfrac{1}{2}\left(\dfrac{E}{2R + \dfrac{{R}_{c}}{2}}\right) \times {R}_{c}
Vg2=ERc4R+Rc{V}_{{g}_{2}} = \dfrac{E{R}_{c}}{4R + {R}_{c}} ....(2)
Since Rc<R2(2Rc<R){R}_{c} < \dfrac{R}{2} \left(2{R}_{c} < R\right)
2R+2Rc<3R2R + 2{R}_{c} < 3R
Vg1>Vg2{V}_{{g}_{1}} > {V}_{{g}_{2}}
Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the

 


iA=ERc{i}_{A} = \dfrac{E}{{R}_{c}}
Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the
Here i=E(2R+2Rc)2R.2Rc=E(R+Rc)2RRci = \dfrac{E ( 2R + 2{R}_{c} )}{2R . 2{R}_{c}} = \dfrac{E ( R + {R}_{c} )}{2R{R}_{c}}
iB=2R2R+2Rc×E(R+Rc)2RRc=E2Rc{i}_{B} = \dfrac{2R}{2R + 2{R}_{c}} \times \dfrac{E ( R + {R}_{c} )}{2R{R}_{c}} = \dfrac{E}{2{R}_{c}}
iA>iB{i}_{A} > {i}_{B}
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