JEE Advanced 2019Paper 2
- Exam
- JEE Advanced
- Year
- 2019
- Paper
- Paper 2
- Subject
- Physics
- Chapter
- Electromagnetic Induction
JEE Advanced 2019 · Paper 2 · Physics · Electromagnetic Induction
A 10cm long perfectly conducting wire PQ is moving, with a velocity...
A long perfectly conducting wire is moving, with a velocity on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor and a resistance as shown in figure. The horizontal rails, lie in the same plane with a uniform magnetic field perpendicular to the plane. If the key is closed at certain instant, the current in the circuit after milli second is where the value of is_______.
[Assume the velocity of wire remains constant after key is closed. Given: where is base of the natural logarithm]
Correct answer
0
Step-by-step solution
⇒ ε = \left(\overset{\to}{v} \times \overset{\to}{B}\right)\overset{\to}{d}l = {10}^{- 2} \times 1 \times {10}^{- 1}\left[\right]