JEE Advanced2019PhysicsElectromagnetic InductionActual
A 10 c m long perfectly conducting wire P Q is moving, with a velocity 1 c m / s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 m H and a resistance R = 1 Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circ
Correct answer
0
Step-by-step solution
⇒ ε = v → × B → d → l = 10 - 2 × 1 × 10 - 1   M o t i o n a l   e m f   i n d u c e d   i n   t h e   r o d ∑ i n d = V → × B → d → l = B . V . l ε = 10 - 3   v o l t ⇒ i = 10 - 3 1 1 - e - 1 → E q u a t i o n   o f   g r o w t h   o f   c u r r e n t   i n   L - R   c i r c u i t   i = ε k 1 - e - t . R L i = 10 - 3 1 - 0.37 i = 0.63   m A