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JEE Advanced 2021Paper 2
Exam
JEE Advanced
Year
2021
Paper
Paper 2
Subject
Physics
Chapter
Experimental Physics

JEE Advanced 2021 · Paper 2 · Physics · Experimental Physics

In order to measure the internal resistance r _ 1 of a cell of emf...

In order to measure the internal resistance r1{r}_{1} of a cell of emf ε,ε, a meter bridge of wire resistance R0=50Ω{R}_{0} = 50Ω, a resistance R02\dfrac{{R}_{0}}{2}, another cell of emf ε2\dfrac{ε}{2} (internal resistance rr) and a galvanometer GG are used in a circuit, as shown in the figure. If the null point is found at l=72cm,l = 72cm, then the value of {r}_{1} = ____Ω .

In order to measure the internal resistance r _ 1 of a cell of emf ε, a meter bridge of wire resistance R _ 0 = 50Ω , a

Correct answer

0

Step-by-step solution

In order to measure the internal resistance r _ 1 of a cell of emf ε, a meter bridge of wire resistance R _ 0 = 50Ω , a

Resistance of potential wire is R0=50Ω{R}_{0} = 50Ω

Resistance of 100cm100cm wire =50Ω= 50Ω

So, Resistance of 72cm72cm wire =50100×72=36Ω= \dfrac{50}{100} \times 72 = 36Ω

Current,

I=ε214+25=εr1+75I = \dfrac{\dfrac{ε}{2}}{14 + 25} = \dfrac{ε}{{r}_{1} + 75}

⇒r1=3Ω⇒ {r}_{1} = 3Ω

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