During Searle's experiment, zero of the Vernier scale lies between...

During Searle's experiment, zero of the Vernier scale lies between $3.20 \times {10}^{- 2}m$ and $3.25 \times {10}^{- 2}m$ of the main scale. The ${20}^{th}$ division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between $3.20 \times {10}^{- 2}m$ and $3.25 \times {10}^{- 2}m$ of the main scale but now the ${45}^{th}$ division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is $8 \times {10}^{- 7}{m}^{2}$ . The least count of the Vernier scale is $1.0 \times {10}^{- 5}m$ . The maximum percentage error in the Young's modulus of the wire is