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JEE Advanced 2013Paper 1

Exam: JEE Advanced
Year: 2013
Paper: Paper 1
Subject: Physics
Chapter: Experimental Physics

JEE Advanced 2013 · Paper 1 · Physics · Experimental Physics

The diameter of a cylinder is measured using a vernier calipers...

The diameter of a cylinder is measured using a vernier calipers with no zero error. It is found that the zero of the vernier scale lies between

5 . 10cm

and

5 . 15cm

of the main scale. The vernier scale has

50

divisions equivalent to

2 . 45cm

. The

{24}^{th}

division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is,

Options

A $5 . 112cm$
B $5 . 124cm$
C $5 . 136cm$
D $5 . 148cm$

Correct answer

B. $5 . 124cm$

Step-by-step solution

\text{1 MSD} = \text{0.05 }

\text{1 VSD} = \dfrac{\text{2.45} }{5 0} = \text{0.04}

\text{Diameter of the cylinder}

~

= \text{MSR} + \text{L.C.} \times 2 4

= \text{5.124 cm}

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