JEE Advanced2006PhysicsExperimental PhysicsActual
The circular scale of a screw gauge has 50 divisions and pitch of 0.5 ~mm . Find the diameter of sphere. Main scale reading is 2 .
Options
- A1.2
- B1.25
- C2.20
- D2.25
Correct answer
A. 1.2
Step-by-step solution
Least count LC = Pitch Number of divisions on circular scale = 0.1 50 =0.01 ~mm Now, diameter of ball =(2 0.5 ~mm )+(25-5)(0.01)=1.2 ~mm