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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Physics
Chapter
Experimental Physics

JEE Advanced 2006 · Physics · Experimental Physics

The circular scale of a screw gauge has 50 divisions and pitch of...

The circular scale of a screw gauge has 50 divisions and pitch of 0.5 mm0.5 \mathrm{~mm}. Find the diameter of sphere. Main scale reading is 2 . The circular scale of a screw gauge has 50 divisions and pitch of 0.5 ~mm . Find the diameter of sphere. Main scale

Options

  1. A1.21.2
  2. B1.251.25
  3. C2.202.20
  4. D2.252.25

Correct answer

A. 1.21.2

Step-by-step solution

Least count LC= Pitch  Number of divisions on circular scale =0.150=0.01\mathrm{LC}=\frac{\text{ Pitch }}{\text{ Number of divisions on circular scale }}=\frac{0.1}{50} =0.01 mm\mathrm{~mm}Now,diameterofballNow, diameter of ball=(2 \times 0.5  mm\mathrm{~mm})+(25-5)(0.01)=1.2  mm\mathrm{~mm}
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