A particle of mass M = 0 . 2 kg is initially at rest in the x y -plane at a point x = − l , y = − h , where l = 10 m and h = 1 m . The particle is accelerated at time t = 0 with a constant acceleration a = 10 m s - 2 along the positive x -direction. Its angular momentum and torque with respect to the origin, in SI units, are represented by L → and τ → , respectively. i ^ , j ^ and k ^ are

Step-by-step solution

At t = 2   s : displacement along + X axis = 1 2 × 10 × t 2 = 1 2 × 10 × 4 = 20   m Hence, particle arrives at 10 , - 1 At x = l ,   y = − h , τ → = r → × F → = 10 i ^ − j ^ × 0 .2 × 10 i ^ = 2 k ^   N   m L → = r → × p → = 10 i ^ − j ^ × 0 .2 × v i ^ and v at   t = 2 s = 0 + 10 × 2 = 20   m   s - 1 ∴     L → = 10 i ^ − j ^ × 4 i ^