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JEE Advanced 2020Paper 1
Exam
JEE Advanced
Year
2020
Paper
Paper 1
Subject
Physics
Chapter
Rotational Motion

JEE Advanced 2020 · Paper 1 · Physics · Rotational Motion

A small roller of diameter 20cm has an axle of diameter 10cm (see...

A small roller of diameter 20cm20cm has an axle of diameter 10cm10cm (see figure below on the left). It is on a horizontal floor and a meter scale is positioned horizontally on its axle with one edge of the scale on top of the axle (see figure on the right). The scale is now pushed slowly on the axle so that it moves without slipping on the axle, and the roller starts rolling without slipping. After the roller has moved 50cm,50cm, the position of the scale will look like (figures are schematic and not drawn to scale) A small roller of diameter 20cm has an axle of diameter 10cm (see figure below on the left). It is on a horizontal

Options

  1. AA solution is prepared by dissolving 0.6 g of urea (molar mass = 60gmol^ - 1 ) and 1.8g of glucose (molar mass =
  2. BA solution is prepared by dissolving 0.6 g of urea (molar mass = 60gmol^ - 1 ) and 1.8g of glucose (molar mass =
  3. CA solution is prepared by dissolving 0.6 g of urea (molar mass = 60gmol^ - 1 ) and 1.8g of glucose (molar mass =
  4. DA solution is prepared by dissolving 0.6 g of urea (molar mass = 60gmol^ - 1 ) and 1.8g of glucose (molar mass =

Correct answer

B. A solution is prepared by dissolving 0.6 g of urea (molar mass = 60gmol^ - 1 ) and 1.8g of glucose (molar mass =

Step-by-step solution

Angular displacement θ=S010=5\theta = \dfrac{{S}_{0}}{10} = 5

A small roller of diameter 20cm has an axle of diameter 10cm (see figure below on the left). It is on a horizontal

Displacement of point BB is,S=r.θ=15×5=75cmS = r . \theta = 15 \times 5 = 75cm

Displacement of roller =50cm= 50cm

Relative displacement =75−50=25cm= 75 - 50 = 25cm

 

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