JEE Advanced 2018Paper 1
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 1
- Subject
- Physics
- Chapter
- Rotational Motion
JEE Advanced 2018 · Paper 1 · Physics · Rotational Motion
Consider a body of mass 1.0kg at rest at the origin at time t = 0 ....
Consider a body of mass at rest at the origin at time . A force \overset{\to}{F} = \left(\alphat\overset{^}{i} + \beta\overset{^}{j}\right) is applied on the body, where . The torque acting on the body about the origin at time . Which of the following statements is (are) true?
Options
- A
- BThe torque is in the direction of the unit vector
- CThe velocity of the body at t = 1sis\overset{\to}{v} = \dfrac{1}{2}\left(\overset{^}{i} + 2\overset{^}{j}\right)m{s}^{- 1}
- DThe magnitude of displacement of the body at
Correct answer
A.
Step-by-step solution
\overset{\to}{F} = \left(\alphat\right)\overset{^}{i} + \beta\overset{^}{j} \left[att = 0, v = 0, \overset{\to}{r} = \overset{\to}{0}\right]\alpha = 1, \beta = 1\overset{\to}{F} = t\overset{^}{i} + \overset{^}{j}m\dfrac{d\overset{\to}{v}}{dt} = t\overset{^}{i} + \overset{^}{j}m\overset{\to}{v} = \dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j}
\dfrac{d\overset{\to}{v}}{dt}\dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j} \left[\overset{\to}{r} = \overset{\to}{0}att = 0\right]\overset{\to}{r} = \dfrac{{t}^{3}}{6}\overset{^}{i} + \dfrac{{t}^{2}}{2}\overset{^}{j}\overset{\to}{τ} = - \dfrac{1}{3}\overset{^}{k}\overset{\to}{v} = \dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j}t = 1\overset{\to}{v} = \left(\dfrac{1}{2}\overset{^}{i} + \overset{^}{j}\right) = \dfrac{1}{2}\left(\overset{^}{i} + 2\overset{^}{j}\right)m / sect = 1\overset{\to}{s} = \overset{\to}{{r}_{1}} - \overset{\to}{{r}_{0}}= \left[\dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}\right] - \left[\overset{\to}{0}\right]\overset{\to}{s} = \dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}
\dfrac{d\overset{\to}{v}}{dt}\dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j} \left[\overset{\to}{r} = \overset{\to}{0}att = 0\right]\overset{\to}{r} = \dfrac{{t}^{3}}{6}\overset{^}{i} + \dfrac{{t}^{2}}{2}\overset{^}{j}\overset{\to}{τ} = - \dfrac{1}{3}\overset{^}{k}\overset{\to}{v} = \dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j}t = 1\overset{\to}{v} = \left(\dfrac{1}{2}\overset{^}{i} + \overset{^}{j}\right) = \dfrac{1}{2}\left(\overset{^}{i} + 2\overset{^}{j}\right)m / sect = 1\overset{\to}{s} = \overset{\to}{{r}_{1}} - \overset{\to}{{r}_{0}}= \left[\dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}\right] - \left[\overset{\to}{0}\right]\overset{\to}{s} = \dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}