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JEE Advanced 2018Paper 1
Exam
JEE Advanced
Year
2018
Paper
Paper 1
Subject
Physics
Chapter
Rotational Motion

JEE Advanced 2018 · Paper 1 · Physics · Rotational Motion

Consider a body of mass 1.0kg at rest at the origin at time t = 0 ....

Consider a body of mass 1.0kg1.0kg at rest at the origin at time t=0t = 0. A force \overset{\to}{F} = \left(\alphat\overset{^}{i} + \beta\overset{^}{j}\right) is applied on the body, where α=1.0Ns−1andβ=1.0N\alpha = 1.0N{s}^{- 1}and\beta = 1.0N . The torque acting on the body about the origin at time =1.0sisτ→= 1.0sis\overset{\to}{τ} . Which of the following statements is (are) true?

Options

  1. A∣τ→∣=13Nm\left|\overset{\to}{τ}\right| = \dfrac{1}{3}Nm
  2. BThe torque τ→\overset{\to}{τ} is in the direction of the unit vector +k→+ \overset{\to}{k}
  3. CThe velocity of the body at t = 1sis\overset{\to}{v} = \dfrac{1}{2}\left(\overset{^}{i} + 2\overset{^}{j}\right)m{s}^{- 1}
  4. DThe magnitude of displacement of the body at t=1sis16mt = 1sis\dfrac{1}{6}m

Correct answer

A. ∣τ→∣=13Nm\left|\overset{\to}{τ}\right| = \dfrac{1}{3}Nm

Step-by-step solution

\overset{\to}{F} = \left(\alphat\right)\overset{^}{i} + \beta\overset{^}{j} \left[att = 0, v = 0, \overset{\to}{r} = \overset{\to}{0}\right]<br><br >\alpha = 1, \beta = 1<br><br >\overset{\to}{F} = t\overset{^}{i} + \overset{^}{j}<br><br >m\dfrac{d\overset{\to}{v}}{dt} = t\overset{^}{i} + \overset{^}{j}<br>Onintegrating<br><br >On integrating<br >m\overset{\to}{v} = \dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j}[m=1kg]\left[m = 1kg\right]
\dfrac{d\overset{\to}{v}}{dt}\dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j} \left[\overset{\to}{r} = \overset{\to}{0}att = 0\right]<br>Onintegrating<br><br >On integrating<br >\overset{\to}{r} = \dfrac{{t}^{3}}{6}\overset{^}{i} + \dfrac{{t}^{2}}{2}\overset{^}{j}<br><br >\overset{\to}{τ} = - \dfrac{1}{3}\overset{^}{k}<br><br >\overset{\to}{v} = \dfrac{{t}^{2}}{2}\overset{^}{i} + t\overset{^}{j}<br>At<br >Att = 1\overset{\to}{v} = \left(\dfrac{1}{2}\overset{^}{i} + \overset{^}{j}\right) = \dfrac{1}{2}\left(\overset{^}{i} + 2\overset{^}{j}\right)m / sec<br>At<br >Att = 1\overset{\to}{s} = \overset{\to}{{r}_{1}} - \overset{\to}{{r}_{0}}<br><br >= \left[\dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}\right] - \left[\overset{\to}{0}\right]<br><br >\overset{\to}{s} = \dfrac{1}{6}\overset{^}{i} + \dfrac{1}{2}\overset{^}{j}<br>∣s→∣=(16)2+(12)2=106m<br > \left|\overset{\to}{s}\right| = \sqrt{{\left(\dfrac{1}{6}\right)}^{2} + {\left(\dfrac{1}{2}\right)}^{2}} = \dfrac{\sqrt{10}}{6}m
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