Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2017Paper 2
Exam
JEE Advanced
Year
2017
Paper
Paper 2
Subject
Physics
Chapter
Rotational Motion

JEE Advanced 2017 · Paper 2 · Physics · Rotational Motion

A wheel of radius R and mass M is placed at the bottom of a fixed...

A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant force is continuously applied on the surface of the wheel so that it just climbs the step without slipping. Consider the torque ττ about an axis normal to the plane of the paper passing through the point Q. Which of the following options is/are correct?
A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant

Options

  1. AIf the force is applied normal to the circumference at point XX then ττ is constant
  2. BIf the force is applied tangentially at point S then τ≠0τ \ne 0 but the wheel never climbs the step
  3. CIf the force is applied normal to the circumference at point P then τ is zero
  4. DIf the force is applied at point P tangentially then ττ decreases continuously as the wheel climbs

Correct answer

B. If the force is applied tangentially at point S then τ≠0τ \ne 0 but the wheel never climbs the step

Step-by-step solution

(i) is incorrect.

A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant

If force is applied normal to surface at point XX

τ=FyRsinθτ = {F}_{y}Rsin \theta

Thus ττ depends on θ\theta and it is not constant

(ii) is incorrect

A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant

If force applied tangentially at S

τ=F×R≠0τ = F \times R \ne 0

But it will climb as mentioned in question.

A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant

If force is applied normal to surface at P then line of action of force will pass from Q and thus τ=0τ = 0

(iv) is incorrect.

A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant

If force is applied at P tangentially the τ=F×2R=constantτ = F \times 2R = constant

Practice Rotational Motion on Quantrex Academy →

More from Rotational Motion

Consider a large disk of radius R and two smaller disks, each of radius r = R/50 , lying… JEE Advanced 2026A solid cylinder of radius R rolls without slipping with a center of mass speed v_0 =… JEE Advanced 2026List-I shows four planar structures made of uniform solid rods each of mass m and length… JEE Advanced 2026Passage: A uniform circular disk of radius 0.2 m and mass 1 kg is pivoted at its top… JEE Advanced 2026Passage: A uniform circular disk of radius 0.2 m and mass 1 kg is pivoted at its top… JEE Advanced 2026A solid cylinder having radius R and length L is slipping on a rough horizontal plane. At… JEE Main 2026A solid sphere ( A ) of mass 5m and a spherical shell ( B ) of mass m , both having same… JEE Main 2026A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through… JEE Main 2026 Full Rotational Motion list All JEE Advanced PYQs