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JEE Advanced 2015Paper 2
Exam
JEE Advanced
Year
2015
Paper
Paper 2
Subject
Physics
Chapter
Rotational Motion

JEE Advanced 2015 · Paper 2 · Physics · Rotational Motion

The densities of two solid spheres A and B of the same radii R vary...

The densities of two solid spheres AA and BB of the same radii RR vary with radial distance rr as ρA(r)=k(rR){ρ}_{A}\left(r\right) = k\left(\dfrac{r}{R}\right) and ρB(r)=k(rR)5{ρ}_{B}\left(r\right) = k{\left(\dfrac{r}{R}\right)}^{5} , respectively, where kk is a constant. The moments of inertia of the individual spheres about axes passing through their centres are IA{I}_{A} and IB{I}_{B} , respectively. If IBIA=n10\dfrac{{I}_{B}}{{I}_{A}} = \dfrac{n}{10} , the value of nn isThe densities of two solid spheres A and B of the same radii R vary with radial distance r as ρ _ A (r) = k((r)/(R))

Correct answer

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Step-by-step solution


The densities of two solid spheres A and B of the same radii R vary with radial distance r as ρ _ A (r) = k((r)/(R))
Consider a shell of radius r and thickness dr
dI=23(dm)r2dI = \dfrac{2}{3}\left(dm\right){r}^{2}
∴dI=23[(krR)4πr2dr]r2∴ dI = \dfrac{2}{3}\left[\left(\dfrac{kr}{R}\right)4\pi{r}^{2}dr\right]{r}^{2}
∫dI=(8π3kR)∫r5dr∫ dI = \left(\dfrac{8\pi}{3}\dfrac{k}{R}\right)∫ {r}^{5}dr
IA=(8\pik3R)(R66){I}_{A} = \left(\dfrac{8\pik}{3R}\right)\left(\dfrac{{R}^{6}}{6}\right)
IA=(8\pik18)R5{I}_{A} = \left(\dfrac{8\pik}{18}\right){R}^{5} ...(i)
Similarly
IB=8kπ3R5∫0Rr9dr{I}_{B} = \dfrac{8k\pi}{3{R}^{5}}{∫}_{0}^{R}{r}^{9}dr
∴IB=8\pik30R5∴ {I}_{B} = \dfrac{8\pik}{30}{R}^{5} ...(ii)
∴IBIA=610∴ \dfrac{{I}_{B}}{{I}_{A}} = \dfrac{6}{10} so n=6n = 6
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