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JEE Advanced 2009Paper 2
Exam
JEE Advanced
Year
2009
Paper
Paper 2
Subject
Physics
Chapter
Rotational Motion

JEE Advanced 2009 · Paper 2 · Physics · Rotational Motion

A sphere is rolling without slipping on a fixed horizontal plane...

A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure, AA is the point of contact. BB is the centre of the sphere and CC is its topmost point. Then, A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure, A is the point of contact. B

Options

  1. Av→C−v→A=2(v→B−v→C)\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A=2\left(\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_C\right)
  2. Bv→C−v→B=v→B−v→A\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_B=\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_A
  3. C∣v→C−v→A∣=2∣v→B−v→C∣\left|\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A\right|=2\left|\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_C\right|
  4. D∣v→C−v→A∣=4∣v→B∣\left|\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_A\right|=4\left|\overrightarrow{\mathbf{v}}_B\right|

Correct answer

B. v→C−v→B=v→B−v→A\overrightarrow{\mathbf{v}}_C-\overrightarrow{\mathbf{v}}_B=\overrightarrow{\mathbf{v}}_B-\overrightarrow{\mathbf{v}}_A

Step-by-step solution

v_A=0, v_B=v  and \text{ and }v_C=2 v A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure, A is the point of contact. B
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