JEE Advanced2023PhysicsThermal Properties of MatterActual
Match the temperature of a black body given in List- I with an appropriate statement in List- II , and choose the correct option. [Given: Wien’s constant as 2 . 9 × 10 - 3 m - K and h c e = 1 . 24 × 10 - 6 V - m ] List- I List- II P 2000 K 1 The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function 4 eV Q 3000 K 2 The radiation at peak wavelength is visible
Options
- AP → 3 ,   Q → 5 ,   R → 2 ,   S → 3
- BP → 3 ,   Q → 2 ,   R → 4 ,   S → 1
- CP → 3 ,   Q → 4 ,   R → 2 ,   S → 1
- DP → 1 ,   Q → 2 ,   R → 5 ,   S → 3
Correct answer
C. P → 3 ,   Q → 4 ,   R → 2 ,   S → 1
Step-by-step solution
Maximum wavelength for each case: P   2000   K λ m T = b ⇒ λ m = b T = 2 . 9 × 10 - 3 2000 = 1 . 45 × 10 - 6   m = 1450   nm ( Q )   3000   K λ m T = b ⇒ λ m = 2 . 9 × 10 - 3 3000 = 966 . 66   nm ( R )   5000   K λ m T = b ⇒ λ m = 2 . 9 × 10 - 3 5000 = 580   nm ( S )   10000   K λ m T = b ⇒ λ m = 2 . 9 × 10 - 3 10 , 000 = 290   nm Now for List- II : 1   λ