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JEE Advanced 2013Paper 1
Exam
JEE Advanced
Year
2013
Paper
Paper 1
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Advanced 2013 · Paper 1 · Physics · Thermal Properties of Matter

Two rectangular blocks, having identical dimensions, can be...

Two rectangular blocks, having identical dimensions, can be arranged either in configuration I\text{I} or in configuration II\text{I}\text{I} as shown in the figure. One of the blocks has thermal conductivity K\text{K} and the other 2 K\text{2 K}. The temperature difference between the ends along the x-axis is the same in both the configurations. It takes 9 s\text{9 s} to transport a certain amount of heat from the hot end to cold end in the configuration I\text{I}. The time to transport the same amount of heat in the configuration II\text{II} is
Two rectangular blocks, having identical dimensions, can be arranged either in configuration I or in configuration II

Options

  1. A2.0 s\text{2.0 s}
  2. B3.0 s\text{3.0 s}
  3. C4.5 s\text{4.5 s}
  4. D6.0 s\text{6.0 s}

Correct answer

A. 2.0 s\text{2.0 s}

Step-by-step solution

In the first combination, the 2 blocks are having thermal conductivity 2K2K and 2K2K respectively are in series combination.

Therefore the Keq will be 1K+12K\dfrac{1}{K} + \dfrac{1}{2K}

and the Keq in case of parallel combination is 3K

Heat transferred=Rate×time. \text{Heat transferred} = \text{Rate} \times \text{time. }
∴Rate1×time1=Rate2×time2.∴ {\text{Rate}}_{1} \times {\text{time}}_{1} = {\text{Rate}}_{2} \times {\text{time}}_{2} .
ΔT×9LKA+L2KA=\DeltaT×tL3KA\dfrac{\Delta \text{T} \times 9}{\dfrac{\text{L}}{\text{KA}} + \dfrac{\text{L}}{2 \text{KA}}} = \dfrac{\text{\Delta} \text{T} \times \text{t}}{\dfrac{L}{\text{3KA}}}
⇒t=2⇒ \text{t} = 2

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