JEE Advanced 2011Paper 1
- Exam
- JEE Advanced
- Year
- 2011
- Paper
- Paper 1
- Subject
- Physics
- Chapter
- Thermal Properties of Matter
JEE Advanced 2011 · Paper 1 · Physics · Thermal Properties of Matter
Steel wire of length L at 40^ C is suspended from the ceiling and...
Steel wire of length at is suspended from the ceiling and then a mass is hung from its free end. The wire is cooled down from to to regain its original length . The coefficient of linear thermal expansion of the steel is , Young's modulus of steel is and radius of the wire is . Assume that diameter of the wire. Then, the value of in is nearly
Correct answer
0
Step-by-step solution
Increase in length Decrease in length To regain its original length,
Substituting the \mathrm{~kg}\therefore$ Answer is 3 .
Analysis of Question
Question is very simple. In my opinion any student who have gone through the syllabus once can solve this problem easily.