A metal rod A B of length 10 x has its one end A in ice at 0^ C and the other end B in water at 100^ C . If a point P on the rod is maintained at 400^ C , then it is found that equal amounts of water and ice evaporate

Correct answer: 0 Heat will flow both sides from point P . aligned L_1 (d m_1)/(d t)& =( Temperature difference Thermal resistance )_1 & =(400)/((λ x) / k A) L_1 (d m_2)/(d t)& =(400-100)/((100-λ) x / k A) aligned In about two equations, aligned & (d m_1)/(d t)=(d m_2)/(d t) (given) & L_1=80 calg^ -1 and L_2=540 calg^ -1 aligned Solving these two equations we get λ=9.

JEE Advanced 2009Paper 2

Exam: JEE Advanced
Year: 2009
Paper: Paper 2
Subject: Physics
Chapter: Thermal Properties of Matter

JEE Advanced 2009 · Paper 2 · Physics · Thermal Properties of Matter

A metal rod A B of length 10 x has its one end A in ice at 0^ C and...

A metal rod

A B

of length

10 x

has its one end

A

in ice at

0^{\circ} \mathrm{C}

and the other end

B

in water at

100^{\circ} \mathrm{C}

. If a point

P

on the rod is maintained at

400^{\circ} \mathrm{C}

, then it is found that equal amounts of water and ice evaporate and melt per unit time. The latent heat of evaporation of water is

540 \mathrm{calg}^{-1}

and latent heat of melting of ice is

80 \mathrm{calg}^{-1}

. If the point

P

is at a distance of

\lambda x

from the ice end

A

, find the value of

\lambda

. [Neglect any heat loss to the surrounding.] A metal rod A B of length 10 x has its one end A in ice at 0^ C and the other end B in water at 100^ C . If a point P