JEE Advanced 2019Paper 1
- Exam
- JEE Advanced
- Year
- 2019
- Paper
- Paper 1
- Subject
- Physics
- Chapter
- Thermodynamics
JEE Advanced 2019 · Paper 1 · Physics · Thermodynamics
One mole of a monoatomic ideal gas goes through a thermodynamic...
One mole of a monoatomic ideal gas goes through a thermodynamic cycle, as shown in the volume versus temperature diagram. The correct statement(s) is/are:
[ is the gas constant]
Options
- AThe ratio of heat transfer during processes 2 \to 3
- BThe ratio of heat transfer during processes 3 \to 4
- CThe above thermodynamic cycle exhibits only isochoric and adiabatic processes.
- DWork done in this thermodynamic cycle is \left|W\right| = \dfrac{1}{2}R{T}_{0}
Correct answer
A. The ratio of heat transfer during processes 2 \to 3
Step-by-step solution
correct
\left(B\right) ⇒ \left|\dfrac{\Delta{Q}_{1 \to 2}}{\Delta{Q}_{3 \to 4}}\right| = \dfrac{{T}_{0}}{{T}_{0} / 2} = 2 ⇒( C ) ⇒⇒( D ) ⇒P - V= {P}_{0}{V}_{0} = nR\dfrac{{T}_{0}}{2}4⇒1 \to 2 ⇒2{P}_{0}2 \to 3 ⇒2{V}_{0}3 \to 4 ⇒{P}_{0}4 \to 1 ⇒{V}_{0}n = 1r = \dfrac{{C}_{P}}{{C}_{V}} = \dfrac{5}{3}\Delta{Q}_{1 \to 2}{=}^{n}{C}_{P} ( {T}_{2} - {T}_{1} )= n ⋅ {C}_{p} ⋅ {T}_{0}\Delta{Q}_{2 \to 3}{=}^{n}{C}_{V}\left({T}_{3} - {T}_{2}\right)