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JEE Advanced 2017Paper 1
Exam
JEE Advanced
Year
2017
Paper
Paper 1
Subject
Physics
Chapter
Thermodynamics

JEE Advanced 2017 · Paper 1 · Physics · Thermodynamics

An ideal gas is undergoing a cyclic thermodynamic process in...

An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams in column 3 of the table. Consider only the path from state 1 to state 2. W denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic process. Here γ\gamma is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is n.
 

Column – 1Column – 2Column – 3
(I) W1→2=1γ−1(P2V2−P1V1){W}_{1 \to 2} = \dfrac{1}{\gamma - 1}\left({P}_{2}{V}_{2} - {P}_{1}{V}_{1}\right)(i) Isothermal(P) An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams
(II) W1→2=−PV2+PV1{W}_{1 \to 2} = - P{V}_{2} + P{V}_{1}(ii) Isochoric(Q) An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams
(III) W1→2=0{W}_{1 \to 2} = 0(iii) Isobaric(R) An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams
(IV) W1→2=−nRTln(V2V1){W}_{1 \to 2} = - nRTln \left(\dfrac{{V}_{2}}{{V}_{1}}\right)(iv) Adiabatic(S) An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams
Which of the following options is the only correct representation of the process ∆U=∆Q−P∆V∆ U = ∆ Q - P ∆ V ?

Options

  1. A(I)(ii)(Q)( I ) ( ii ) ( Q )
  2. B(IV)(ii)(R)( IV ) ( ii ) ( R )
  3. C(III)(iv)(R)( III ) ( iv ) ( R )
  4. D(I)(iv)(Q)( I ) ( iv ) ( Q )

Correct answer

D. (I)(iv)(Q)( I ) ( iv ) ( Q )

Step-by-step solution

The correct match is (I) (iv) (Q)
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