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A diatomic ideal gas is compressed adiabatically to 1 32 of its initial volume. If the initial temperature of the gas is T_iT_i (in kelvin) and the final temperature is a T_i , the value of a is

Correct answer

0

Step-by-step solution

In adiabatic process, aligned & T V^ -1 = constant & T_i V_i^ 0.4 =T_f V_f^ 0.4 & (as =1.4 for diatomic gas) & or T_i V_i^ 0.4 = ( T_i ) ( V_i 32 )^ 0.4 & or (32)^ 0.4 =4 & aligned The correct answer is 4 .

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