JEE Advanced2006PhysicsThermodynamicsActual
Match the following for the given process
Options
- A(a) s, (b) p, r, (c) r, (d) q,s
- B(a) r, (b) p, s, (c) q, (d) q
- C(a) s, (b) p, r, (c) q, (d) q
- D(a) r, (b) p, s, (c) r, (d) q,s
Correct answer
A. (a) s, (b) p, r, (c) r, (d) q,s
Step-by-step solution
(a) s (b) p , r , (c) r (d) q , s In process J K : V is constant whereas P is decreasing, Therefore, T should also decrease. W=0, U=- ve and Q 0, U>0 and Q>0 In process L M : This is inverse of process J K . W=0, U>0 and Q>0 In process M J : V is decreasing. Therefore, W < 0 array lcl & (P ~V )_J & < (P V)_M & T_J & < T_M or U < 0 Therefore, & Q & < 0 . array No, solution is required.