In the Claisen-Schmidt reaction to prepare (351 ~g) of...

In the Claisen-Schmidt reaction to prepare (351 \mathrm{~g}) of dibenzalacetone using (87 \mathrm{~g}) of acetone, the amount of benzaldehyde required is ______ g. (Nearest integer)

Correct answer

Step-by-step solution

Claisen Schmidt reaction In the Claisen-Schmidt reaction to prepare (351 ~g) of dibenzalacetone using (87 ~g) of acetone, the amount of

mw of benzaldehyde

=106

106 \times 3=318 \mathrm{gm}

. Benzaldehyde is required to give 1.5 mole (or

351 \mathrm{gm}

) product

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