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JEE Main 202430 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Aldehydes and Ketones

JEE Main 2024 · 30 January · Evening Shift · Chemistry · Aldehydes and Ketones

m-chlorobenzaldehyde on treatment with 50 % KOH solution yields

m-chlorobenzaldehyde on treatment with 5050 %KOHKOH solution yields

m-chlorobenzaldehyde on treatment with 50 % KOH solution yieldsm-chlorobenzaldehyde on treatment with 50 % KOH solution yieldsm-chlorobenzaldehyde on treatment with 50 % KOH solution yieldsm-chlorobenzaldehyde on treatment with 50 % KOH solution yieldsm-chlorobenzaldehyde on treatment with 50 % KOH solution yields

Options

  1. AStatement I: For colloidal particles, the values of colligative properties are of small order as compared to values
  2. BStatement I: For colloidal particles, the values of colligative properties are of small order as compared to values
  3. CStatement I: For colloidal particles, the values of colligative properties are of small order as compared to values
  4. DStatement I: For colloidal particles, the values of colligative properties are of small order as compared to values

Correct answer

D. Statement I: For colloidal particles, the values of colligative properties are of small order as compared to values

Step-by-step solution

Meta–chlorobenzaldehyde will undergo Cannizzaro reaction with 5050 % KOH to give mchlorobenzoate ion and m−m -chlorobenzyl alcohol. 

Since m−m -chlorobenzaldehyde does not contain α hydrogen thus with 5050 % KOH it undergoes the Cannizzaro reaction. The Cannizzaro reaction for the m−m -chlorobenzaldehyde is given as:

m-chlorobenzaldehyde on treatment with 50 % KOH solution yieldsSince it is a disproportionation reaction so one molecule of m−m -chlorobenzaldehyde is reduced to m−m -chlorobenzyl alcohol at the \cos t of others which is oxidized potassium m−m -chlorobenzoate.

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