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JEE Main 202331 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Aldehydes and Ketones

JEE Main 2023 · 31 January · Morning Shift · Chemistry · Aldehydes and Ketones

Consider the following reaction Propanal + Methanal = → _ ( ii ) Δ...

Consider the following reaction

Propanal + Methanal = \mathop{\to}_{( ii ) \Delta ( iii ) NaCN ( iv ) {H}_{3}{O}^{+}}^{( i ) dil . NaOH}P\mathop{roductB}_{( {C}_{5}{H}_{8}{O}_{3} )}</p><p>Thecorrectstatementforproduct</p><p>The correct statement for productB$ is. It is

Consider the following reaction Propanal + Methanal = → _ ( ii ) Δ ( iii ) NaCN ( iv ) H _ 3 O ^ + ^ ( i ) dil . NaOH P

Options

  1. Aoptically active and adds one mole of bromine
  2. Bracemic mixture and is neutral
  3. Cracemic mixture and gives a gas with saturated NaHCO3{NaHCO}_{3} solution
  4. Doptically active alcohol and is neutrall

Correct answer

C. racemic mixture and gives a gas with saturated NaHCO3{NaHCO}_{3} solution

Step-by-step solution

Propanal and methanal undergo aldol condensation reaction with sodium hydroxide. The α,β\alpha, \beta-unsaturated compound undergo 1,4−1, 4 -conjugated addition with cyanide ion gives a racemic mixture. The cyanide undergo acidic hydrolysis gives carboxylic acid.

Consider the following reaction Propanal + Methanal = → _ ( ii ) Δ ( iii ) NaCN ( iv ) H _ 3 O ^ + ^ ( i ) dil . NaOH P

Carboxylic acid will give CO2{CO}_{2} gas, with NaHCO3{NaHCO}_{3} solution

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