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JEE Main 20209 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
9 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Aldehydes and Ketones

JEE Main 2020 · 9 January · Evening Shift · Chemistry · Aldehydes and Ketones

Consider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^...

Consider the following reactions A(i)CH3MBr(ii)H3O+BCu573K2−methyl−2−buteneA\dfrac{\left(i\right)C{H}_{3}MBr}{( ii ) {H}_{3}{O}^{+}}B\dfrac{Cu}{573K}2 - methyl - 2 - butene . The mass percentage of carbon in AA is _____________.Consider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The massConsider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The massConsider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The mass

Correct answer

0

Step-by-step solution

Consider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The massConsider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The mass
Compound A is Consider the following reactions A (i)C H _ 3 MBr ( ii ) H _ 3 O ^ + B(Cu)/(573K)2 - methyl - 2 - butene . The mass
Percentage carbon in compound A= (12×448+16+8×100)=66.67\left(\dfrac{12 \times 4}{48 + 16 + 8} \times 100\right) = 66.67
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