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JEE Main2014ChemistryAldehydes and KetonesActual

In the reaction, CH 3 COOH → LiAlH 4 A → PCl 5 B → Alc. KOH C , the product C is :

Options

  1. AAcetaldehyde
  2. BAcetylene
  3. CEthylene
  4. DAcetyl chloride

Correct answer

C. Ethylene

Step-by-step solution

LiAlH 4 is a reducing agent and reduces carboxylic acid to alcohol. CH 3 COOH → LiAlH 4 CH 3 - CH 2 - OH (A) → PCl 5 CH 3 - CH 2 - Cl → KOH alc  CH 2 = CH 2

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