Match List I with List II List-I List-II A. Glucose/ NaHCO _ 3 / ∆ I. Gluconic acid B. Glucose/ HNO _ 3 II. No reaction C. Glucose/ HI / ∆ III. n -hexane D. Glucose/Bromine water IV. Saccharic acid Choose the correct

Question

Quantrex Academy · Accepted Answer

Correct answer: B. A-II, B-IV, C-III, D-I

Glucose → _ ∆ ^ NaHCO _ 3 noreaction Glucose → _ ∆ ^ HNO _ 3 saccharicacid Glucose, on oxidation with nitric acid, gives saccharic acid. Glucose → _ ∆ ^ HI n - hexane Glucose, on prolonged heating with hot HI, gives n-Hexane. Glucose → _ ∆ ^ Br _ 2 Gluconicacid Glucose reacts with bromine water to form gluconic acid. Bromine water is a mild oxidising agent which selectively oxidizes aldehyde to carboxylic acid only. It doesn’t oxidise alcohol or ketone. Hence option B is the answer.

Match List I with List II List-I List-II A. Glucose/ NaHCO _ 3 / ∆...

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More from Biomolecules

	List-I		List-II
A.	Glucose/ ${NaHCO}_{3} / ∆$	I.	Gluconic acid
B.	Glucose/ ${HNO}_{3}$	II.	No reaction
C.	Glucose/ $HI / ∆$	III.	$n$ -hexane
D.	Glucose/Bromine water	IV.	Saccharic acid