JEE Main202431 Jan 2024Morning ShiftChemistryBiomoleculesActual
Match List I with List II List-I List-II A. Glucose/ NaHCO 3 / ∆ I. Gluconic acid B. Glucose/ HNO 3 II. No reaction C. Glucose/ HI / ∆ III. n -hexane D. Glucose/Bromine water IV. Saccharic acid Choose the correct answer from the options given below:
Options
- AA-IV, B-I, C-III, D-II
- BA-II, B-IV, C-III, D-I
- CA-III, B-II, C-I, D-IV
- DA-I, B-IV, C-III, D-II
Correct answer
B. A-II, B-IV, C-III, D-I
Step-by-step solution
Glucose → ∆ NaHCO 3 no reaction Glucose → ∆ HNO 3 saccharic acid Glucose, on oxidation with nitric acid, gives saccharic acid. Glucose → ∆ HI n - hexane Glucose, on prolonged heating with hot HI, gives n-Hexane. Glucose → ∆ Br 2 Gluconic acid Glucose reacts with bromine water to form gluconic acid. Bromine water is a mild oxidising agent which selectively oxidizes aldehyde to carboxylic acid only. It doesn’t oxidise alcohol or ketone. Hence option B is the answer.