An athlete is given 100g of glucose ( C _ 6 H _ 12 O _ 6 ) for energy. This is equivalent to 1800kJ of energy. The 50 % of this energy gained is utilized by the athlete for sports activities at the event. In order to

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Overall reaction of metabolism of glucose in the body:
${C}_{6}{H}_{12}{O}_{6} ( s ) + 6{O}_{2} \to 6{CO}_{2} ( g ) + 6{H}_{2}O ( l )$

Extra energy used to convert ${H}_{2}O ( l )$ into ${H}_{2}O ( g )$ , energy left

$= \dfrac{1800}{2} = 900kJ$
Moles of water vaporised from enthalpy of evaporation:

$⇒ 900 = {n}_{{H}_{2}O} \times 45$

${n}_{{H}_{2}O} = \dfrac{900}{45} = 20\text{mole}$

${W}_{{H}_{2}O} = 20 \times 18 = 360g$

An athlete is given 100g of glucose ( C _ 6 H _ 12 O _ 6 ) for...

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