JEE Main202325 Jan 2023Morning ShiftChemistryBiomoleculesActual
An athlete is given 100 g of glucose C 6 H 12 O 6 for energy. This is equivalent to 1800 kJ of energy. The 50 % of this energy gained is utilized by the athlete for sports activities at the event. In order to avoid storage of energy, the weight of extra water he would need to perspire is _____g (Nearest integer) Assume that there is no other way of consuming stored energy. Given : The enthalpy of evaporation of water
Correct answer
0
Step-by-step solution
Overall reaction of metabolism of glucose in the body: C 6 H 12 O 6 (   s ) + 6 O 2 → 6 CO 2 (   g ) + 6 H 2 O ( l ) Extra energy used to convert H 2 O ( l ) into H 2 O ( g ) , energy left = 1800 2 = 900   kJ Moles of water vaporised from enthalpy of evaporation: ⇒ 900 = n H 2 O × 45 n H 2 O = 900 45 = 20  mole  W H 2 O = 20 × 18 = 360   g