2 . 5g of protein containing only glycine ( C _ 2 H _ 5 NO _ 2 ) is...

\pi = CRT$</p><p>$5 . 03 \times {10}^{- 3} = \left[\dfrac{2 . 5 \times 1000}{M . wt \times 500}\right] \times 0 . 083 \times 300$</p><p>M.wt.$= 24 . 752 \times {10}^{3}gram = 24752gram$</p><p>Molar mass of glycine \left({NH}_{2}{CH}_{2}COOH\right) = 75g / Mol$.

No of glycine unit in protein $= \dfrac{24752}{75} = 330 . 02 ≃ 330units$