Which of the following is correct structure of α -anomer of maltose?

Which of the following is correct structure of

\alpha

-anomer of maltose? Which of the following is correct structure of α -anomer of maltose?

Options

A $Consider the function f(x) = \ cases (x - 4). ^ -1 ((1)/(x - 4))& x ≠ 4 0 & x = 4 cases ,) then$
B $Consider the function f(x) = \ cases (x - 4). ^ -1 ((1)/(x - 4))& x ≠ 4 0 & x = 4 cases ,) then$
C $Consider the function f(x) = \ cases (x - 4). ^ -1 ((1)/(x - 4))& x ≠ 4 0 & x = 4 cases ,) then$
D $Consider the function f(x) = \ cases (x - 4). ^ -1 ((1)/(x - 4))& x ≠ 4 0 & x = 4 cases ,) then$

Correct answer

A. $Consider the function f(x) = \ cases (x - 4). ^ -1 ((1)/(x - 4))& x ≠ 4 0 & x = 4 cases ,) then$

Step-by-step solution

$\alpha$ -ANOMER OF MALTOSE

maltose is disaccharides of $\alpha$ - $D$ - glucopyranose by ${C}_{1} - {C}_{4}$ glycosidic linkage

Which of the following is correct structure of α -anomer of maltose?

Maltose or malt sugar is a disaccharide composed of two glucose molecules connected with an alpha (1,4) glycosidic bond.

Maltose is a reducing sugar. It's two glucose molecules must be linked in such a way as to leave one anomeric carbon that can open to form an aldehyde group.

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