JEE Main201910 Jan 2019Evening ShiftChemistryBiomoleculesActual
The correct match between item I and item II is Item I (Compound) Item II (Reagent) a . Lysine p . 1 - naphthol b . Furfural q . Ninhydrin c . Benzyl alcohol r . KMnO 4 d . Styrene s . Ceric ammonium nitrate
Options
- Aa → q ,   b → r ,   c → s ,   d → p
- Ba → q ,   b → p ,   c → s ,   d → r
- Ca → r ,   b → p ,   c → q ,   d → s
- Da → q ,   b → p ,   c → r ,   d → s
Correct answer
B. a → q ,   b → p ,   c → s ,   d → r
Step-by-step solution
Lysine → Ninhydrin (this is given out by all the amino acids and Lysine is an amino acid.) Furfural → 1 - naphthol. Rapid furfural test is used to distinguish between glucose and fructose. In this test, the sugar solution is added to 1 - naphthol and concentrated HCl . Benzyl alcohol → ceric ammonium nitrate. Ceric ammonium nitrate test is used for testing of alcohols. Styrene undergoes oxidation when treated with KMnO 4 .