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JEE Main 202628 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

JEE Main 2026 · 28 January · Evening Shift · Chemistry · Carboxylic Acid Derivatives

The correct order of acidic strength of the major products formed...

The correct order of acidic strength of the major products formed in the given reactions, is :
A. The correct order of acidic strength of the major products formed in the given reactions, is : A. B. CH_ 3 CH_ 2 CHO
B. CH3CH2CHO→Δ[Ag(NH3)2]+,OH−[B]\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO} \xrightarrow[\Delta]{\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}, \mathrm{OH}^{-}}[\mathrm{B}]
C. CH4+O2→ (ii) Na2Cr2O7/H+(i) [C]\mathrm{CH}_{4}+\mathrm{O}_{2} \xrightarrow[\text{ (ii) } \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} / \mathrm{H}^{+}]{\text{(i) }}[\mathrm{C}]
D. PhCH2MgBr+CO2→H3O+Dry ether [D]\mathrm{PhCH}_{2} \mathrm{MgBr}+\mathrm{CO}_{2} \xrightarrow[\mathrm{H}_{3} \mathrm{O}^{+}]{\text{Dry ether }}[\mathrm{D}]
Choose the correct answer from the options given below :

Options

  1. AA>D>B>CA>D>B>C
  2. BC>A>D>BC>A>D>B
  3. CC>B>A>DC>B>A>D
  4. DA>D>C>BA>D>C>B

Correct answer

B. C>A>D>BC>A>D>B

Step-by-step solution

Product [A]: From PhNH₂, steps (1) NaNO₂ + HCl forms diazonium salt, (2) CuCN gives benzonitrile, (3) H₃O⁺/Δ hydrolyzes to benzoic acid (PhCOOH), pKa ≈ 4.2.
Product [B]: From CH₃CH₂CHO, Tollens' oxidation with [Ag(NH3)2]+[Ag(NH_3)_2]^+ produces acetic acid (CH₃COOH), pKa ≈ 4.8.
Product [C]: From CH₄ + O₂ with heat and Na₂Cr₂O₇/H⁺ produces formic acid (HCOOH), pKa ≈ 3.8 (strongest acid).
Product [D]: From PhCH₂MgBr + CO₂, the Grignard reaction produces phenylacetic acid (PhCH₂COOH), pKa ≈ 4.3.
Acidic strength order (lower pKa = stronger): C (3.8) > A (4.2) > D (4.3) > B (4.8).
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