Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20236 Apr 2023Morning ShiftChemistryChemical EquilibriumActual

For a concentrated solution of a weak electrolyte ( K eq = equilibrium constant) A 2 B 3 of concentration ‘ C ’ , the degree of dissociation ‘ α ’ is

Options

  1. AK eq 5 c 4 1 5
  2. BK eq 108 c 4 1 5
  3. CK eq 25 c 2 1 5
  4. DK eq 6 c 5 1 5

Correct answer

B. K eq 108 c 4 1 5

Step-by-step solution

Given that concentration of A 2 B 3 is C and degree of dissociation is α The equilibrium reaction of weak electrolyte A 2 B 3 is A 2   B 3 ⇌ 2   A 3 + + 3   B 2 - C - - ↓ ↓ ↓ C ( 1 - α ) 2 C α 3 C α Now, The equilibrium constant is the ratio of the concentrations of reactants and products raised to the stoichiometric coefficients. K eq = ( 2 Cα ) 2 ( 3 Cα ) 3 C ( 1 - α ) = 108 C 4 α 5 K eq 108 C 4 = α 5 ⇒ α = K eq 108 C 4

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in gaseous state 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ The value of K₃ for the 2026Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = 0.08 atm C (s) + CO ₂(g) 2 CO (g) K_ p₂ = 2 atm The partial pres 2026In a closed flask at 600 K, one mole of X₂ Y₄ (g) attains equilibrium as given below : X ₂ Y ₄(g) 2 XY ₂(g) At equilibrium, 75 % X₂ Y₄ (g) was dissociated and the total pressure is 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) B(g) . K_c for this reaction at 400 K is 4.0 . The pa 2026The reaction A(g) B(g) + C(g) was initiated with the amount ' a ' of A(g) . At equilibrium it is found that the amount of A(g) remaining is (a - x) at a total pressure of p . The e 2026The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) 1 T ( K ⁻¹) ₁₀ K_p 0.05 2026For the following reaction at 50° C and at 2 atm pressure, 2N₂O₅(g) 2N₂O₄(g)+O₂(g) N₂O₅ is 50 % dissociated. The magnitude of standard free energy change at this temperature is x . 2026At T(K) , the equilibrium constant of A₂(g) + B₂(g) C(g) is 2.7 10⁻⁵ . What is the equilibrium constant for 1 3 A₂(g) + 1 3 B₂(g) 1 3 C(g) at the same temperature? 2026 Full Chemical Equilibrium list All JEE Main PYQs