For reaction: SO 2 ( g ) + 1 2 O 2 ( g ) ⇌ SO 3 ( g ) K P = 2 × 10 12 at 27 ° C and 1 atm pressure. The K c for the same reaction is × 10 13 . ( Nearest integer) (Given R = 0 . 082 L atm K - 1 mol - 1 )

Step-by-step solution

For reaction: SO 2 ( g )   +   1 2 O 2 ( g )   ⇌   SO 3 ( g ) K p   =   2 × 10 12 at 300   K and 1   atm pressure. The relation between equilibrium constant in terms of pressures K p and equilibrium constant in terms of concentration K c is K p   =   K c   ×   ( RT ) ∆ n g ⇒   2 × 10 12   =   K c   ×   ( 0 . 082   ×   300 ) - 1 2 ⇒   K C =   9 . 92   × &