At 298 K N 2 g + 3 H 2 g ⇌ 2 NH 3 g , K 1 = 4 × 10 5 N 2 g + O 2 g ⇌ 2 NO g , K 2 = 1 . 6 × 10 12 H 2 g + 1 2 O 2 g ⇌ H 2 O ( g ) , K 3 = 1 . 0 × 10 - 13 Based on above equilibria, the equilibrium constant of the reaction, 2 NH 3 g + 5 2 O 2 ( g ) ⇌ 2 NO g + 3 H 2 O g is _____ × 10 - 33 (Nearest integer)

Step-by-step solution

Given, N 2 g 3 H 2 g ⇌ 2 NH 3 g , K 1 = 4 × 10 5                     … 1 N 2 g + O 2 g ⇌ 2 NO g , K 2 = 1 . 6 × 10 12                 … 2 H 2 g + 1 2 O 2 g ⇌ H 2 O g , K 3 = 1 . 0 × 10 - 13             … 3 Using properties of equilibrium constant: 2 + 3 × 3 - 1 2 NH 3 g + 5 2 O 2 g ⇌ 2 NO g + 3 H 2 O g K eq = K 2 × K 3 3 K 1 = 1 .