Water decomposes at 2300 K H 2 O g → H 2 g + 1 2 O 2 g The percent of water decomposing at 2300 K and 1 bar is _____ (Nearest integer). Equilibrium constant for the reaction is 2 × 10 - 3 at 2300 K

Step-by-step solution

Decomposition of water gives: H 2 O g   ⇌   H 2 g   +   1 2 O 2 g P 0 1 - α        P 0 α               P 0 α 2 partial pr. at eq. Thus, P 0 1 + α 2 = 1                         … 1 K p = P H 2 P O 2 1 / 2 P H 2 O P 0 α P 0 α 2 1 / 2 P 0 1 - α = 2 × 10 - 3 since α is negligible w.r.t 1 thus, 1 - α ≈ 1 ⇒ α &