2 NOCl g ⇌ 2 NO g + Cl 2 g In an experiment, 2 . 0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0 . 4 mol / L . The equilibrium constant at 30 ° C is_____ × 10 - 4 .

Step-by-step solution

2 NOCl g ⇌ 2 NO g + Cl 2 g t = 0 2   M t = t eq 2 - x M xM x 2 M ∵   x = 0 . 4   M ∴   NOCl eq = 1 . 6   M NO eq = 0 . 4   M Cl 2 eq = 0 . 2   M ⇒ K c = NO 2 Cl 2 NOCl 2 = 0 . 4 2 0 . 2 1 . 6 2 K c = 32 2 . 56 × 10 - 3 K c = 12 . 5 × 10 - 3 K c = 125 × 10 - 4 Integer answer is 125