Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2022 · 25 June · Morning Shift · Chemistry · Chemical Equilibrium

The standard free energy change (Δ G °) for 50 % dissociation of N...

The standard free energy change (ΔG°)\left(\Delta G °\right) for 5050 % dissociation of N2O4{N}_{2}{O}_{4} into NO2{NO}_{2} at 27°Cand1atm27 ° C and 1atm pressure is −xJmol−1- xJ{mol}^{- 1}. The value of xx is −.....J- . . . . . J. (Nearest Integer)

[Given : R=8.31JK−1mol−1,log⁡1.33=0.1239ln⁡10=2.3R = 8 . 31J{K}^{- 1}{mol}^{- 1}, \log 1 . 33 = 0 . 1239\ln 10 = 2 . 3]

Correct answer

0

Step-by-step solution

N2O4(g)⇌2NO2(g){N}_{2}{O}_{4}\left(g\right) ⇌ 2{NO}_{2}\left(g\right)

1−α2α1 - \alpha2\alpha

Kp=4α2p1−α2=4×(0.5)2×11−(0.5)2=10.75{K}_{p} = \dfrac{4{\alpha}^{2}p}{1 - {\alpha}^{2}} = \dfrac{4 \times {\left(0 . 5\right)}^{2} \times 1}{1 - {\left(0 . 5\right)}^{2}} = \dfrac{1}{0 . 75}

Kp=43{K}_{p} = \dfrac{4}{3}

ΔGo=−2.303RTlogKp{\Delta G}^{o} = - 2 . 303RTlog{K}_{p}

=−2.3×8.31×300[log43]=−2.3×8.31×300×0.1239= - 2 . 3 \times 8 . 31 \times 300\left[log\dfrac{4}{3}\right] = - 2 . 3 \times 8 . 31 \times 300 \times 0 . 1239

=−710J= - 710J

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in… JEE Main 2026Solid carbon, CaO and CaCO _3 are mixed and allowed to attain equilibrium at T K.… JEE Main 2026In a closed flask at 600 K, one mole of X _2 Y _4 (g) attains equilibrium as given below… JEE Main 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to… JEE Main 2026The reaction A(g) leftharpoons B(g) + C(g) was initiated with the amount ' a ' of A(g) .… JEE Main 2026The values of pressure equilibrium constant recorded at different temperatures for the… JEE Main 2026For the following reaction at 50° C and at 2 atm pressure, 2N_2O_5(g) leftharpoons… JEE Main 2026At T(K) , the equilibrium constant of A_2(g) + B_2(g) leftharpoons C(g) is 2.7 × 10^ -5 .… JEE Main 2026 Full Chemical Equilibrium list All JEE Main PYQs