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The reaction rate for the reaction PtCl 4 2 - + H 2 O ⇌ Pt H 2 O Cl 3 - + Cl - was measured as a function of concentrations of different species. It was observed that - d PtCl 4 2 - dt = 4 . 8 × 10 - 5 PtCl 4 2 - - 2 . 4 × 10 - 3 Pt H 2 O Cl 3 - Cl - where square brackets are used to denote molar concentrations. The equilibrium constant K c = X (Nearest integer) Value of 1 X i s (question is modified.

Correct answer

0

Step-by-step solution

K C = K f K b = 4 . 8 × 10 - 5 2 . 4 × 10 - 3 = 2 × 10 - 2 Value   of   1 K c   =   50 Note: This question is modified from the original.

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