The OH - concentration in a mixture of 5 . 0 mL of 0 . 0504 M NH 4 Cl and 2 mL of 0 . 0210 M NH 3 solution is x × 10 - 6 M . The value of x is (Nearest integer) [Given K w = 1 × 10 - 14 and K b = 1 . 8 × 10 - 5

Step-by-step solution

NH 4 Cl = NH 4 + = 0 . 0504 M    V = 5 . 0   mL NH 3 = 0 . 0210 M    V = 2 . 0   mL K b = NH 4 + OH - NH 3 OH - = K b × NH 3 NH 4 + = 1 . 8 × 10 - 5 × 0 . 0210 × 2 0 . 0504 × 5 = 3 × 10 - 6 M